Math Help: Box Rotation
BlitzMax Forums/BlitzMax Programming/Math Help: Box Rotation
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| I have a central point, and an orientation, I need to find the position of 4 points that make up a square around the box but my googling abilities are failing me... Given the position 10,10, an orientation of 0deg, and a box size of 4 units the points would be (clockwise starting from upper left). x | y -------- 8 | 12 12| 12 12| 8 8 | 8 total brain fart, I think it has to do with the pythagorean theorem, but I can't recall how to work the angle into it. any help would be much appreciated. |
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| corner1X=radius*cos(angleOfBox)+x corner1Y=radius*sin(angleOfBox)+y corner2X=radius*cos(angleOfBox+90)+x corner2Y=radius*sin(angleOfBox+90)+y and so on. You'll likely need to add an offset to the angleOfBox in order to get it to appear flat at 0 degrees though. Cheers Charlie |
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| double post Last edited 2012 |
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| you can look at my my box rotated collision code in the code arch see if it helps: http://www.blitzmax.com/codearcs/codearcs.php?code=2806 Last edited 2012 |
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| Aaah, excelent thank you muchly! |
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