13 digit number rounding and full visible
BlitzMax Forums/BlitzMax Beginners Area/13 digit number rounding and full visible
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| Hi, I'm new to Blitzmax (... Blitz-anything actually). Currently i'm in the building a 2D side scrolling adventure fase (read: beginner) and somehow i ended up making an application for work. But making this application will give me more time at work.... to read the Blitz forum :) I'm using MaxGui to show 2 inputboxes. In inputbox 1 a user types a 13 digit number In inputbox 2 (outputbox) i show the number converted to a 12 digit number. Why? Well at my work we have a unique identifier for persons but we are not allowed to communicate that number to the outside world. We send information with a 'encryption', a math conversion to a different number (13 digits) to keep the person unique but to make identifying the person very difficult. In some cases we get the encrypted number back and we need to decrypt it. But because the math conversion needs to be kept on a 'need to know' basis i have to decrypt the number for others. To save myself and my colleges from this menial work i'm making a conversion tool. It's easy, i made it for myself in Excel but i can't give that to others because they can see the formula. I ran into 2 problems: 1. After reading a lot on the forum i used different rounding functions but none work with 13 digit numbers. 2. After conversion the number is displayed like this: 5.08356485e+010. But it should be like this: 123456789012 Does anyone have an idea how to fix this? |
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| Use doubles instead of floats. Not sure if you'll quite manage 13 digits, but you should get closer. |
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| I think there is a funny behavior within the compiler: Try this: SuperStrict Local Test1:Long = 1234567890:Long Local Test2:Long = 12345678901:Long Local Test3:Long = 123456789012:Long Const MAXLONG:Long=$7fffffffffffffff:Long Const MINLONG:Long=$8000000000000000:Long Print "A long can have the maximum value of:"+MAXLONG Print "A long can have the minimum value of:"+MINLONG Print Test1 Print Test2 Print Test3 |
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| @Gabriel: thanx for your input but i already use Double. @robobimbo: I will try it at home as soon as i'm done with work.. which isn't for another 8 hours. But shouldn't i use Double instead of Long? I really hope that if i can make this in Excel it's also possible in BlitzMax. Anyone an idea on how to display the full 12 digits output instead of the 1,345634E23 output? |
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| do you generate integer numbers oder do you have to handle decimal numbers? (floating point) |
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This converts doubles in various ways between strings/doubles, and always appears to display as expected :SuperStrict Local bigNum:Double = 1234567890123:Double Local bigString:String = "1234567890123" Print bigNum Print bigString Local test:String = bigNum Print test test = String.FromDouble(bigNum) Print test bigNum = test.ToDouble() Print bigNum test = String.FromDouble(bigNum) Print test ' some math bigNum = bigNum/10 Print bigNum bigNum = Floor(bigNum) Print bigNum test = String.FromDouble(bigNum) Print test my output, on XP SP2, bmx 1.30 1234567890123.0000 1234567890123 1234567890123.0000 1234567890123.0000 1234567890123.0000 1234567890123.0000 123456789012.30000 123456789012.00000 123456789012.00000 |
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| @Brucey: You are my saviour! Many thanx. Somehow my gut feeling tells me the Floor function will just discard whatever is behind the komma, is my assumption right? I need to round the number up where the numbers behind the komma are >= .5 and down where < .5. |
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| You can always add .5 and then Floor(). |
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| Eh... yeah that will actually work, thanx. Next time i'll think before asking. You just made yourself some excellent advertisement for you mods Brucey :) |
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