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Ummm, len()? or...

BlitzMax Forums/BlitzMax Beginners Area/Ummm, len()? or...

Garrett(Posted 2006) [#1]
Well, I feel like a total newb today! :-)

How on Blitz Earth do I get the length of either a int variable and ditto for a
string variable?

Here's what I was doing:
  Local vLineNow  = TextAreaCursor(vTextEdit,TEXTAREA_LINES) + 1
  Local vLineAll  = TextAreaLen(vTextEdit,TEXTAREA_LINES) + 1
  Local vRawLine  = TextAreaCursor(vTextEdit,TEXTAREA_LINES)
  Local vCharNow  = TextAreaCursor(vTextEdit,TEXTAREA_CHARS) - TextAreaChar(vTextEdit,vRawLine)
  Local vLinePad  = Len(vLineAll)
  Local vPadding$ = ""
  Local vCurrPad  = Len vCharNow + Len vPadding$
  If vCurrPad <> vLinePad
    Repeat
      vPadding$ = vPadding$ + "."
      vCurrPad  = Len vCharNow + Len vPadding$
    Until vCurrPad = vLinePad
  EndIf
  SetStatusText(vWindow,"Ln:  " + vPadding$ + vLineNow + "    Col:  " + vCharNow + "    " + vLinePad + "|" + vCurrPad)

But the len isn't working. Likely it's something I'm doing wrong, but after
hitting the docs for about an hour, haven't found my mistake or a solution.

Can anybody slap me in the face with an answer to this?

Thanks,
-Garrett


Hotcakes(Posted 2006) [#2]
1) Not sure about int vars, but strings have a method called Length... ie length_of_string=vPadding.Length()

2) This may have broken in the latest version of Max. Safe usage of Len requires brackets at the moment... ie Local vCurrPad = Len(vCharNow)+Len(vPadding$)

3) I could be wrong. =]

Related links:
http://www.blitzbasic.com/Community/posts.php?topic=62888
http://www.blitzbasic.com/Community/posts.php?topic=62674#701278


H&K(Posted 2006) [#3]
It has been reported that the presedent order for LEN (Which is an operator and not a function) is broken in 1.22, so as a sudgestion put brakets round (Len vCharNow)+(Len VPadding)

EDIT: should have been a bit quicker ther shouldnt I?
Interesting that we have chosen to put the brackets in different places tho.


kenshin(Posted 2006) [#4]
I must be wierd or something 'cause I've always been using Len(vCharNow).

Must be a throwback from the bad 'ole days. Well, that's my excuse anyway.


Garrett(Posted 2006) [#5]
Well, I'm at a loss. Nothing seems to work for len on strings or integers :-(

Thanks anyway everyone,
-Garrett


Jesse(Posted 2006) [#6]
I use: 
c$="car"
b% = 123
print c.length
print string(b).length

for strings and int. works fine for me


tonyg(Posted 2006) [#7]
Len and length works on objects.
Strings are objects but ints are not.
car:String="Ferrari"
price:Int=100000
Print Len(car)
' or
Print car.length
Print Len(String(price))
'or
Print String(price).length



Dreamora(Posted 2006) [#8]
Length of an int doesn't make any sense anyway.

Length in what? It is just a number in memory.
For drawing it needs to be a string, where length makes a sense.


Yan(Posted 2006) [#9]
Just to clarify what's already been said...
Local vLinePad  = Len(vLineAll)
...
vCurrPad  = Len vCharNow + Len vPadding$
Makes no sense, It's just...
Local vLinePad  = vLineAll
...
vCurrPad  = vCharNow + vPadding$.length ' I don't see the point of Len() TBH. ;o)



Garrett(Posted 2006) [#10]
The point was that I needed to know how many characters in length the int
variable held. Such as, if was only 1 character such as "7", or whether it held
2 characters such as "77" or whether it held 3 characters such as "777".

In the end, I was trying to place line numbers and column location on the
status bar, but pad the line numbers in a way that kept the column count from
being moved when the user went from say line 9 to line 10, and then the
column count on the status bar would be moved over by a character. So if total
lines was 498, I need a total of 3 characters constantly for the line number.

So if the user is on line 7, then I need to pad it with two extra spaces to make
up the difference, such as " 7", or if the user is on line 77, then I only need to
pad with one extra space, such as " 77".

I guess I'll just convert the integers to strings and then get the len.

Thanks,
-Garrett


Jesse(Posted 2006) [#11]
why don't you use "rset" or "Lset"? Rset works like this:
b:int = 25
a$ = rSet(String(b),5) 'creates a string 5 char. long padded to the left
Print a$
Print Len(a$)



Garrett(Posted 2006) [#12]
why don't you use "rset" or "Lset"? Rset works like this:


I.... I.... Ummmmmm.... Being old and stupid is my excuse I tell you! ;-)

I'll give that a try :-)

Thanks Jesse,
-Garrett