equidistant point inside a spline
BlitzMax Forums/BlitzMax Beginners Area/equidistant point inside a spline
| ||
| Hi ! i know how to draw a spline, but in my game i need equidistant points along the path ! Is there a formulae to do this ? i'm crap with math ! Thanks for your help from my ingame code : spline For Local a:Float=0 To 1 - .01 Step .01 t.x[Index] = x1*(1-a)^3 + 3*vx1*(1-a)^2*a + 3*vx2*(1-a)*a^2 + x2*a^3 t.y[Index] = y1*(1-a)^3 + 3*vy1*(1-a)^2*a + 3*vy2*(1-a)*a^2 + y2*a^3 Index = Index + 1 Next Note that you can see the problem if you download my game, press f2 during the introscreen (cheat mode) and with the arrows keys choose level 10. ( http://www.bayre.com/zigwigwis/ to download click on 'telecharger') |
| ||
| As you draw the lines, count how many pixels are in the line, or work out how distant the points are apart, and split them if needed.? |
| ||
ThanksMyStep# = 0.0 a# = 0 index = 0 While a < 1 a = a + MyStep t.x[Index] = x1*(1-a)^3 + 3*vx1*(1-a)^2*a + 3*vx2*(1-a)*a^2 + x2*a^3 t.y[Index] = y1*(1-a)^3 + 3*vy1*(1-a)^2*a + 3*vy2*(1-a)*a^2 + y2*a^3 vx#= -3 * x1 * (1-a)^2 + 3 * vx1 * (1-a) * ((1-a)-2*a) + 3 * vx2 * a * (2*(1-a)-a) + x2 * 3 * a^2 vy#= -3 * y1 * (1-a)^2 + 3 * vy1 * (1-a) * ((1-a)-2*a) + 3 * vy2 * a * (2*(1-a)-a) + y2 * 3 * a^2 d#=Sqr(vx * vx + vy * vy) MyStep# = Speed/d Index = Index + 1 Wend Thanks to Warpy : http://www.blitzbasic.com/codearcs/codearcs.php?code=1523 |
   |