Updating enemys
BlitzMax Forums/BlitzMax Beginners Area/Updating enemys
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| I´m currently trying to add enemys to my game, i guess each of them (3 different enemys) will have their own type since they are going to behave very differently, and as i create these different enemys i add them to a list wich my update and draw funtions process. What i wonder is how i´m suposed to update all my different enemys, i mean the "eachin" command i´m using in my "for" loop only acesses one type of enemy in the list, do i have to make three "for" loops to update all of them? or is there a better way, and does the same principle apply when i check the collision, i´m i bit worried in that case becuase it´s gonna be alot of loops before everythings checked if i have to divide everything up. As for the collision at this point i´m first looping through all enemys to see if the player collides with any of them, then i´m looping through every enemy and checks each of them against all active bullets fired by the player (i´m checking the collision maually so to speak with rectangles, not with the imagecollide commands). I´m also wondering wich loop structure that is best suited for this as well. Any tips would be very appreciated. |
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| Presumably all your enemies share similar methods for the most part, although the implementation may be different. if so, create an abstract parent type and derive the enemies from that. then store them all in the same list. i.e.
Type TBaseEnemy
Method Update() abstract
End Type
Type TWarg extends TBaseEnemy
Method Update()
'update your warg
End Method
End Type
Type TOgre extends TBaseEnemy
Method Update()
'update your ogre
End Method
End Type
Type TTroll extends TBaseEnemy
Method Update()
'update your troll
End Method
End Type
As for the collision at this point i´m first looping through all enemys to see if the player collides with any of them, then i´m looping through every enemy and checks each of them against all active bullets fired by the player Wouldn't it be better to perform both checks at the same time? thereby saving yourself a loop? |
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| Perty to the rescue |
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