collision radius

Blitz3D Forums/Blitz3D Programming/collision radius

ryan scott

(Posted 2004) [#1]

i'm confused about entityradius.

previously there was only the x parameter. i guess it made a sphere with radius x.

now we have a y parameter. that's nice, but without also an z parameter i'm confused as to what the collision area actually looks like.

watch, i'm trying to show myself the collision radius, and defining it too (note you have to have a centered mesh for this to work, so included both routines)

Function centerMESH(entity)
	FitMesh entity, -(MeshWidth (entity) / 2), -(MeshHeight (entity) / 2), -(MeshDepth (entity) / 2), MeshWidth (entity), MeshHeight (entity), MeshDepth (entity)
End Function

Function AutoRadius(entity)
	EntityRadius entity, MeshWidth (entity)+.2, MeshHeight (entity)+.2
	If SHOW_ENTITY_COLLISION_AREAS
		x=CreateSphere(8,entity)
		FitMesh x, -(.2+MeshWidth (entity) / 2), -(.2+MeshHeight (entity) / 2), -(.2+MeshWidth (entity) / 2), .2+MeshWidth (entity), .2+MeshHeight (entity),.2+MeshWidth (entity)
		EntityAlpha x,.7
		EntityColor x,0,255,0
	EndIf	
End Function
; the .2 is just adding a little more.

i'm confused - is the sphere shape like this?

x,y,x

or x,y,y?

that is, if you set x and y to say, 10 and 5

will you get a sphere that is stretched to fix a box 10 long, 5 heigh, and how many wide? 5 or 10 or some other number?

seems like we need a 3rd parameter. or docs clarification

jfk EO-11110

(Posted 2004) [#2]

the x parameter is also used for z.