Functions as Types?
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| Why doesn't this work? ('troop' and 'unit' are previously defined Types), it's the '\checked' bit it doesn't seem to like. ; ; FindTroopLeader(troop)\checked = True ; ; Function FindTroopLeader.unit(troop.troop) For this.unit = Each Unit If this\troop = troop If this\leader = True Return this.unit EndIf EndIf Next End Function If I use an array it works fine, such as... claimedNode(x,y)\checked = true where claimedNode is defined as.. Dim claimedNode.unit(48,48) |
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| 2 things. 1) I would change the function call with: temp = FindTroopLeader(troop) temp\checked = true where temp is declared as temp.troop 2) I would distinguish between type structure name and type pointer name; in your example, troop is the type structure name, and also the type pointer name, which I find a bit confusing. So, make your type structure always with t_ suffix, for example: type t_troop field... end type global troop.t_troop Hope this helps, Sergio. |
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| Thanks for the reply Sergio. I tried your suggestion 1) and it works great. I was hoping there was a way to avoid creating a 'temp' Type just to check the result of a Function, just seems like redundant code to me, especially when it seems to work fine with Arrays. Thanks again for the help. Also, do you always define your Types as Global? I pass all my Types between Functions and have never needed to make them Global, is there another reason? |
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| No, I declare them global only for code consistence, but it is not needed, a type pointer becomes global the moment you declare it. So this: troop.t_troop has the same effect of: global troop.t_troop More, since you return a troop element (this), you can just refer to that, since the for..next loop has exited, that means that 'this' points already to the right element. In other words, you may do like: FindTroopLeader(troop) this\checked = true ;'this' points already to the element you want to edit That's why I think, also, that you can set the 'checked' field of 'this' element, directly in the FindTroopLeader function: Function FindTroopLeader.unit(troop.troop) For this.unit = Each Unit If this\troop = troop If this\leader = True ;Return this.unit this\checked = true return EndIf EndIf Next End Function That means also that the function declaration does not need to return any 'unit' type, so you can declare it as: Function FindTroopLeader(troop.troop) Hopefully I didn't confuse you ! Sergio. |
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| A little bit confused, but more concerned that all my Type pointers used in Functions survive outside the function, if I understand what you are saying? I also don't want to set the \leader field inside the FindTroopLeader function because I call that function from lots of different places in the code for other reasons. Thanks for the advice and info. |
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| troop.t_troop has the same effect of: global troop.t_troop I don't think so. :) If you want a type pointer (or any other type of variable) to be accessible inside functions, you have to specifically declare them as Global, in the main code. MAX711, you're OK - local function variables are destroyed on exiting the function and so are not accessible outside of functions. |
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